- Change in stars with latitude
- Objects being hidden by the curve of the earth
- Measured distances (and aircraft flight times) between cities
- Need I go on?
As a result of gravity working this way, the gravitational force at the earth's surface on an object of mass
m is:
F = 6.67408×10^-11
M m /
r^2 = 9.8
m
where
M is the mass of the earth, and
r its radius.
Force = mass times acceleration, so:
F =
m a = 9.8
m
Therefore
a = 9.8. That is, ignoring air resistance, all falling objects close to the earth's surface accelerate at 9.8 metres per second per second, no matter how heavy they are.
"where M is the mass of the earth, and r its radius." LOL, .. this is a perfect example how the Germans at NASA were able to brainwash U.S. college kids who were first made to believe they are evolving mindless animals of the ape family while in kindergarten.
I think you've got force, acceleration, and speed confused. They are three different things.
Really? I thought Force = acceleration = speed?
Now if gravity existed, the feather would have it's own pulling force on the earth, and the 8,000 times more massive bowling ball would have 8,000 times the g-force, or pulling-on-the-earth-force than the feather, now try adding numbers, not letters.
In letters, G is gravity, the feather has 'G' and the bowling ball has 'G', as well as your Globe has 'G'. So you and NASA can avoid using actual numbers, you add G+G+G=G and say: "See, they all have the same 'G', so they fall at the same rate, at 'G'!" .. LOL.
Give up? Are you ready to accept that the bowling ball should have fallen faster than the feather? Or are you going to figure in the radius of the bowling ball and the circumference of the feather into the simple drop?
Remember, NASA and Brian Cox
"expected" that no matter what the mass/size difference of the objects, meaning even if it was a pin and an object the size of the moon, or a rock 8,000 times the size of the moon, they will drop at the same rate, and reach the bottom at the same time!
This proves they never used real numbers to figure any moon/planet landings, which means they never went to imaginary space, but just did what you just did above, .. or used their symbol-idol E=MC^2 for everything.