The discussion from what I recall is how does the momentum p of an object changes as the velocity reaches relativistic speeds.
At low speeds the momentum is p = mv but as the speed increases to relativistic magnitudes
p = mv/√(1-v²/c²)
Does the mass M increase relativistically M = mv/√(1-v²/c²), or does the velocity V increase V = v/√(1-v²/c²)?
Mathematically both variations are valid but since mass and charge are properties of an object and charge remains invariant (does not increase with increasing velocity), the modern day preference is for the mass M to remain invariant as well.
It's about the frame of reference, an observer on earth will measure the clock on a spaceship running slower compared to his own clock.
The reason why your GPS works is that atomic clocks on GPS satellites need to be adjusted to take into consideration gravitational time dilation effects of general relativity and velocity effects of special relativity to remain synchronized with atomic clocks on Earth.
It doesn’t work that way.
From a classical physics perspective to accelerate an object of mass m from rest to some velocity v, work W needs to be performed on the object and equals the change in KE (kinetic energy) in this case W = (1/2)mv².
At relativistic speeds however the change in KE = mc²/√(1-v²/c²) - mc² where mc² is the rest energy.
If v = c the mc²/√(1-v²/c²) term becomes infinitely large irrespective of the value of constant acceleration.
It doesn't matter what the magnitude of the constant acceleration is, eventually the speed of light is reached which requires an infinite amount of energy.
Particle accelerators are examples of this limitation, its no coincidence the LHC accelerates protons to 99.999999% the speed of light.
There is a law of diminishing returns as increasing the particle accelerator centre of mass energies does not produce significant increases in particle velocities as the speed of light is the limit.