Edwin Wright
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- Mar 23, 2023
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I appreciate your armchair review, but seriously, a joke is a joke. The Plane Geodesy article takes pains to point out the conceptual difference between angular velocity and linear (in this case, radially-dependent tangential) velocity, hence the merry-go-round analogy as follows:No need. I have what I need on your site.
From here: Heliocentrism Refuted: Experimental Proof of a Stationary Earth
'After flying almost due south for about 5 hours at an (alleged) west → east tangential velocity of 397km hr less than that of the arrival runway at BOG, Avianca Flight AV21 would soon realize that their destination (i.e., the arrival runway at BOG) was 1,985km (i.e., 5hr×397km hr) east of the aircraft’s position — now flying over the Pacific Ocean about 625km north-northwest (NNW) of the Galápagos Islands.'
It seems like the guy who wrote that has realised that as we live on a spherical world then Bogota is moving laterally eastward quicker than NY. It's as if you were at the equator and walked around the world it would take you a couple of years, but if you were standing at the north pole it would take you a couple of minutes. But...he then concludes that if the world was a sphere then Bogota moves around the planet quicker than NY (no, that's seriously the point he is making). Because he is confusing lateral speed with angular velocity. It's as monstrously dumb as saying that the bottom of a tall building would move around the world slower than the top because the speed at the bottom is slower than the speed at the top.
Yep, that is exactly what his argument is. And pointing out the difference between linear and angular velocity should be enough. It's covered in junior school. Angular velocity Facts for Kids
If that is too much for our friends at planegeodesy then may be they could simply get hold of a globe, draw a line between NY and Bogota and then spin the globe. Do the cities change position in relationship to each other? Spoiler alert...no, they don't.
And as for the plane sitting on the runway at NY... It's lateral speed in any direction to the runway way is zero. Exactly the same as it's lateral speed in any direction relative to the runway way in Bogota. So when it takes off it follows that line that was drawn on the globe. And will not find itself after a few hours, to the express astonishment of some people here, in the Galapagos Islands.
"But the reader need not be too concerned with such technical matters. One only has to visit an amusement park merry-go-round to fully understand the underlying concept of a stationary earth. From the perspective of tangential velocity, a rotating disk (i.e., the merry-go-round) is conceptually equivalent to a rotating sphere or spheroid (i.e., the (allegedly) spheroidal, rotating earth). (See [Note 1] below.) Have one person stand near the center of the merry-go-round (where the tangential velocity is low) and another person stand near its periphery (where the tangential velocity is much higher). Have the person near the center attempt to throw a soccer ball to the person near the periphery. Assuming counterclockwise rotation of the merry-go-round (relative to the person near the center facing outward—conceptually equivalent to the (allegedly) counterclockwise rotation of the earth relative to Avianca Flight AV21 from New York flying south), unless the person near the center throws the soccer ball sufficiently counterclockwise of the person near the periphery, the soccer ball will exit the merry-go-round somewhat clockwise of the person near the periphery, just as Avianca Flight AV21 (originating in New York and therefore nearer to the (so-called) North Pole or rotational axis of the (allegedly) spheroidal, rotating earth) would be over the Pacific Ocean approximately 625km NNW of the Galápagos Islands upon reaching the latitude of Bogotá (i.e., clockwise of the airport at Bogotá located just under 5° from the equator and therefore close to the periphery or maximum rotational radius of the (allegedly) spheroidal, rotating earth).
"[Note 1] The essential concept being that for both a disk and a sphere (or spheroid) rotating at a constant angular velocity, the tangential velocity is directly and exclusively proportional to the radial distance from the rotational axis."
But wait, don't take my word for it, National Geographic is saying the EXACT same thing in respect of (in this case) a south-to-north flight from Texas to Nebraska, but with the added caveat that the airplane compensates for the latitudinal differences in tangential velocity (which it doesn't because the earth is stationary). See https://planegeodesy.com/blog-a-pla...ic-video-implies-that-the-earth-is-stationary.
But getting back to that tall building, first of all, the building is NOT moving around the earth but is (allegedly) moving with the (allegedly) rotating earth. And so the top of the building (being farther away from the center of the allegedly rotating spheroidal earth) would indeed be moving faster (tangentially) than the bottom of the building.
A stationary plane on the runway at either location is obviously not moving RELATIVE to the runway but would be moving WITH the allegedly rotating earth at the same angular velocity but with different tangential velocities. The only problem is, the plane would never have landed because its New York tangential velocity would never have caught up with the Bogotá tangential velocity. Unfortunately, it would have been somewhere NNW of the Galápagos Islands. But not to worry, because the earth is a stationary plane, allowing daily worldwide aviation. It's that simple.
Thank you for your interest in Plane Geodesy.
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