Not sure.
With density and buoyancy, in a vacuum, because there is nothing opposing their movement, I think they just fall at maximum rate. Not sure what defines the rate, but its probably independent of the mass and density.
As far as I can tell, gravity doesn't explain this. Why is gravity treated as an acceleration in this case exactly? If gravity is a force, then it should follow F=ma, so the object with more mass should fall slower, so how does falling at the same rate "confirm" gravity is working?
The level of ignorance displayed in this post is astonishing.
First of all it is nonsensical to talk about buoyancy in a vacuum.
When an object is immersed in a medium such as air or water it displaces a volume of the medium (heard of Archimedes?)
The weight of the displaced medium is the buoyant force Bf which acts in the opposite direction to the gravitational force which is F=mg, the weight of the object, where g is the acceleration due to gravity.
If Bf > F then the object floats in the medium such as a helium balloon in air.
Firstly, earth is special. The things you see above are not earthy things, not made of rocks etc. The moon is transparent. Have you ever seen the other side of the moon? The sun, moon, and the stars are moving clockwise above the earth (center of motion being the north pole - the center of the earth; also there is no south pole), the wondering stars (the "other planets") have the sun as their center of circular motion.
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So the moon is not made out of rock?
I suppose the Apollo missions to the moon where fakes when the astronauts “supposedly” returned with lunar rocks along with samples collected by unmanned Soviet and later on by Chinese missions.
Then there are the lunar meteorites found on Earth.
Randy Korotev who takes no prisoners as I know from experience would have a field day with you.
There is no South Pole?
Heard of the celestial pole which is a projection of the Earth’s North or South Pole onto the sky?
In the northern hemisphere stars appear to move counterclockwise around the NCP (North Celestial Pole) where as they move clockwise around the SCP.
It’s very difficult to explain motion around the SCP if there is no South Pole.
How do you explain being an Australian from Perth you are unable to observe the Northern Pole star Polaris if the Earth is flat.
Since you seem to going on about a geocentric model as well explain how stars exhibit
parallax if the earth is stationary?
See my point about gravity in the "same rate in a vacuum" section. Furthermore, the weight of objects do not change between midday and midnight, so how can gravity and the solar system be true? I would expect that objects would weight less at midday compared to midnight because at midday the earth's and sun's gravitational pull would oppose each other on an object (causing it to weigh less), while at midnight, they would work together (causing it to weigh more). Obviously, this does not occur.
What makes you think it doesn’t?
Here is a bit of maths.
Newton’s law of gravitational attraction is F = Gm₁m₂/r²
Let’s consider a man of weight 80 kg (mass ≈ 8 kg).
We can consider the change of force Δf on an 80 kg mass between the near and far side distance of the Earth to the Sun.
This is simply Δf =G(Mm)/(R-r)²-G(Mm)/(R+r)²
G is the gravitational constant = 6.67 x 10⁻¹¹ m³ kg⁻¹ s⁻²
M is the mass of the Sun= 1.98 x10³⁰ kg
m = 80 kg.
R is the Earth-Sun distance = 1.5 x 10¹¹ m
r is the Earth’s radius = 6.371x 10⁶ m
(R-r) and (R+r) are the near and far side distances respectively.
Plugging in the values give Δf ≈ 0.08g which is a negligible difference.