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Solve the riddle for 1,000,000 blessings!

sempre dolce

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Here's a tougher one! Good luck with it :)

I'm a four-digit number! My 2nd digit is twice greater than my 3rd. The sum of all my digits is thrice greater than my last digit! The product of my 3rd and 4th digits is 12 times greater than the ratio of my 2nd to 3rd. What am I?


***ETA This riddle is now worth 50,000,000 blessings! C'mon mathletes, let's go! :clap:
 
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