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Riddle - Can you guess the answer?

Crazynutt

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Sorry Purpleunicorn_Andi....the answer must be between 1000 and 2000, this makes it easier... :p

Given people are finding this so hard, I will up the reward...

The reward is now... 150 blessings...


Is that better???

Keep trying. You might get it someday... (hehehe)

Crazynutt :wave:
 
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deaduser

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I think I know. Its almost all of them. You can do 1000 and 2000 cause they are even numbers that are multiples of 5, and you can do all the odd numbers.

With the rest of the even numbers you have to see if they are multiples of an odd number. example 1000/5=200 so then you can say 198+199+200+201+202=1000
here are some others

1001=500+501

1002=333+334+335

1003=501+502

1005=502+503

1007=503+504

1008=335+336+337

1009=504+505

1010=200+201+202+203+204

1011=505+506

1013=506+507

1014=337+338+339

1015=507+508

1017=508+509

1019=509+510

1020=339+340+341

1021=510+511

1023=511+512

1025=512+513

1026=341+342+343

1027=513+514

1029=514+515

................

2000=398+399+400+401+402
 
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~ Gig ~

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Here's a bit of help, odd numbers and multipules of odd numbers are already blue numbers.

For any odd number X, if X-1=Y, then Y/2+(Y/2+1)=X


For any multipul of 3, X, then (X/3-1)+(X/3)+(X/3+1)=X
For any multipul of 5, X, then (X/3-2)+(X/3-1)+(X/3)+(X/3+1)+(X/3+2)=X

So, since multipules of odd numbers and odd numbers themselves are out, then all that are left are powers of two. (2, 4, 8, 16, 32,)

HOWEVER, 2 can be eached by these numbers: (-1)+0+1+2
4 can be reached by this: (-3)+(-2)+(-1)+0+1+2+3+4.
In short, X can be reached by (-(X-1))+....+0+....X
 
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Crazynutt

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Deaduser, please remember that the question is:
Crazynutt said:
[size=-1]A quick math riddle for you:
Question: Can you find all the numbers that can't be called blue numbers
between 1000 and 2000 and prove your answers.

[/size]


All the ones you have given are blue...this is not the answer you need... Sorry....


But keep trying, you are almost there!!!


Crazynutt :wave:
 
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Woody

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deaduser said:
I think I know. Its almost all of them. You can do 1000 and 2000 cause they are even numbers that are multiples of 5, and you can do all the odd numbers.

With the rest of the even numbers you have to see if they are multiples of an odd number. example 1000/5=200 so then you can say 198+199+200+201+202=1000
here are some others

1001=500+501

1002=333+334+335

1003=501+502

1005=502+503

1007=503+504

1008=335+336+337

1009=504+505

1010=200+201+202+203+204

1011=505+506

1013=506+507

1014=337+338+339

1015=507+508

1017=508+509

1019=509+510

1020=339+340+341

1021=510+511

1023=511+512

1025=512+513

1026=341+342+343

1027=513+514

1029=514+515

................

2000=398+399+400+401+402

Well i'm liking your effort dude!! :thumbsup:

haaa....i might try it when i am old and have nothing better to do......
 
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gods_vocalist

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Ive probly got it completely wrong and just wasted almost an hour trying to work it out but, here goes all the same

1004, 1006, 1012, 1016, 1018, 1022, 1024, 1028, 1034, 1036, 1042, 1046, 1048, 1052, 1054, 1058, 1064, 1066, 1072, 1076, 1078, 1082, 1084, 1088, 1094, 1096, 1102, 1104, 1106, 1112, 1116, 1118, 1122, 1124, 1128, 1134, 1136, 1142, 1146, 1148, 1152, 1154, 1158, 1164, 1166, 1172, 1176, 1178, 1182, 1184, 1188, 1194, 1196, 1202, 1204, 1206, 1212, 1216, 1218, 1222, 1224, 1228, 1234, 1236, 1242, 1246, 1248, 1252, 1254, 1258, 1264, 1266, 1272, 1276, 1278, 1282, 1284, 1288, 1294, 1296, 1302, 1304, 1306, 1312, 1316, 1318, 1322, 1324, 1328, 1334, 1336, 1342, 1346, 1348, 1352, 1354, 1358, 1364, 1366, 1372, 1376, 1378, 1382, 1384, 1388, 1394, 1396, 1402, 1404, 1406, 1412, 1416, 1418, 1422, 1424, 1428, 1434, 1436, 1442, 1446, 1448, 1452, 1454, 1458, 1464, 1466, 1472, 1476, 1478, 1482, 1484, 1488, 1494, 1496, 1502, 1504, 1506, 1512, 1516, 1518, 1522, 1524, 1528, 1534, 1536, 1542, 1546, 1548, 1552, 1554, 1558, 1564, 1566, 1572, 1576, 1578, 1582, 1584, 1588, 1594, 1596, 1602, 1604, 1606, 1612, 1616, 1618, 1622, 1624, 1628, 1634, 1636, 1642, 1646, 1648, 1652, 1654, 1658, 1664, 1666, 1672, 1676, 1678, 1682, 1684, 1688, 1694, 1696, 1702, 1704, 1706, 1712, 1716, 1718, 1722, 1724, 1728, 1734, 1736, 1742, 1746, 1748, 1752, 1754, 1758, 1764, 1766, 1772, 1776, 1778, 1782, 1784, 1788, 1794, 1796, 1802, 1804, 1806, 1812, 1816, 1818, 1822, 1824, 1828, 1834, 1836, 1842, 1846, 1848, 1852, 1854, 1858, 1864, 1866, 1872, 1876, 1878, 1882, 1884, 1888, 1894, 1896, 1902, 1904, 1906, 1912, 1916, 1918, 1922, 1924, 1928, 1934, 1936, 1942, 1946, 1948, 1952, 1954, 1958, 1964, 1966, 1972, 1976, 1978, 1982, 1984, 1988, 1994, 1996
 
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Crazynutt

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Gods_vocalist...I am amazed...
How on earth did you do it?

One of those answers is correct...I am sorry to say, you do not win, because all the rest are incorrect...

I will give you another clue...this might make it a little easier...the one number of those typed above which is correct is near the start....

P.S. It is not the first one...

Please remember, you are looking for the number(s) which cannot be called blue numbers...(Numbers which cannot be made from two or more consecutive numbers)... Keep going. Please!!!


Good luck
Crazynutt :wave:
 
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~ Gig ~

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God is Gracious said:
Here's a bit of help, odd numbers and multipules of odd numbers are already blue numbers.

For any odd number X, if X-1=Y, then Y/2+(Y/2+1)=X


For any multipul of 3, X, then (X/3-1)+(X/3)+(X/3+1)=X
For any multipul of 5, X, then (X/3-2)+(X/3-1)+(X/3)+(X/3+1)+(X/3+2)=X

So, since multipules of odd numbers and odd numbers themselves are out, then all that are left are powers of two. (2, 4, 8, 16, 32,)

HOWEVER, 2 can be eached by these numbers: (-1)+0+1+2
4 can be reached by this: (-3)+(-2)+(-1)+0+1+2+3+4.
In short, X can be reached by (-(X-1))+....+0+....X


The answer is 1024. If you allowed negative numbers then the answer becomes trivial.
 
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Crazynutt

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God is Gracious said:
The answer is 1024. If you allowed negative numbers then the answer becomes trivial.



God is Gracious...I am proud to announce, that...

You have won...150 blessings...Congratulations....And people said it was too hard!!!! (tut, tut)

Well done, those blessing will be in your post box soon than you can repeat the answer!!!

AGAIN!!!
Congratulation God is Gracious, YOU HAVE WON!!!!

WOOT, WOOHOO!!! THE CROWD GOES WILD ...etc.


Crazynutt :wave:
 
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gods_vocalist

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My turn to add a riddle


If anyone can get this riddle, they will be awarded 50 blessings


While exploring the wild highlands of Scotland, Crazy Rob was captured by hostile wood fairies.

Smazze, the powerful chief of the fairies told him he could make one final statement which would determine how he would die.

If the statement he made was false, he would be boiled in water.

If the statement were true, he would be fried in oil.

Crazy Rob found neither of this options too his liking, so he made a statement that got him out of this seemingly impossible situation.

What is the one statement he could make to save himself?
 
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