Now you say there are no dates. So tell us how the first data point on your pic got there?
Here is the standard equation that I am using, but with one difference:
The difference is that we are going to take
t out of the equation. Since you don't like it in there, let's take it out. Instead, let's replace
t with scientific observations. Let's have the U/Pb equation on one side of the equal sign, and the K/Ar on the other side of the equal sign. Just for clarification, we are using 235U and 40K which have observed decay constants of 9.846E-10 year and 5.540E-10 respectively. Again, these are the OBSERVED decay constants. No assumptions of long time periods are being used.
The equation will look like this:
[ln[1+(Pb/U)]]/9.84E-10=[ln[1+(Ar/K)]]/5.540E-10
What is the prediction based on? How do we confirm it?
This is the prediction:
[ln[1+(Pb/U)]]/9.84E-10=[ln[1+(Ar/K)]]/5.540E-10
It is based on the observed decay rate of both U and K. In a geologic stratum, if you are able to measure the Pb/U ratio in an appropriate sample, you can predict what the Ar/K ratio should be in a matching appropriate sample. All you have to do is plug the Pb/U ratio into the equation and solve for Ar/K. All I did was plug several different Pb/U ratios in, and solved for Ar/K for each of those Pb/U ratios. That's what those points on the graph are. That's were all of the points should land if the rocks were formed in a same state past. I even gave you the equation where it is solved for Ar/K
(EXP((LN(1+A2))*($F$2/$E$2))-1)
Where A2 is the Pb/U ratio, F2 is the 235U decay constant, and E2 is the 40K decay constant. The formula can be drag copied in column B with Pb/U ratios in column A
What you showed assumed same state decay.
Predictions aren't assumptions. If the measured ratios in these rocks do not match the line on that graph, then they did not form in a same state past. That's the test.
Explain in your own words how the first data point is a 'constant'? How was this constant observed?
K decays directly to Ar. What you do is take a known amount of K and count how many disintegrations occur per second in something like a scintillation counter. That gives you the decay constant. It is something that undergradutate physics students do in college.
http://www.chymist.com/Half life of potassium 40.pdf
Ever heard of algebra? Think "solve for x", except you are solving the equation for Ar/K.
In the real world what does that mean? Where is the first data point from? How do we find this in reality? Example? In what way is the data point real?
In reality, we find this in the rocks. Let's say we find a sedimentary layer that has both zircons and sanidine crystals from a volcanic eruption. You measure the ratio of Pb/U in the zircons, and it is 1 (equal amounts of Pb/U). I find 1.0 on the x-axis of my graph and follow it up until it intersects with my line at about 0.45 on the y-axis. I predict that when you measure the sanidine samples they will have a Ar/K ratio of about 0.45. Not 3.0. Not 0.1. It will be consistently at 0.45 within the margin of error of measurement.
That is the prediction.
Trendline? In other words the trend of there being more or less of certain isotopes? How would that help you or relate to the far past? You need some reason to draw pics and claim trends.
The reason is that we should see a 0.45 Ar/K ratio if the Pb/U ratio is 1.0 if that layer of rock formed in a same state past. That is what the math tells us.
In other words the present state decay produces ratios also. Inverse ones perhaps. We don't know. One cannot say though, that the trend of decaying existed before this state did! Only the ratios.
You are blabbering again. You are making zero sense.
Also, you have no way to place time to your data points! Boy are you hooped!
Show us two data points in the real world that do fall in your non time line!
Are you saying that I have to include millions of years into the equations before you will accept them as evidence?
You mean the present state decay constant!
If there was a different state past then the decay constant would be different, and the trendline would be different. Therefore, rocks that form in a different state past will not fall on the trendline created by using the same state decay constants. That is the test. If there was a different state past then the ratios will not fall on that trendline.