Within the core of a Star, as the Hydrogen atoms &, or elements [sup]2[/sup][sub]1[/sub]H & [sup]3[/sup][sub]1[/sub]H scatter off the dense gas particles in the interior & move about a centimeter between collisions (i.e., Nuclear Fusion & Nuclear Fission which involves entropic nuclear reactions) & in each collision they transfer some of their energy to the gas particles & by the space ▲ the time Photons finally reach the photosphere of the Sun.... the high energy electromagnetic gamma radiation particle rays that they once was they're no-longer, because they've now become the Photons of a much lower energy radiation, or luminous particles (i.e., visible light).
Note: Since the core of any active Star(s) posses extreme density, heat & is under extreme pressure via electromagnetic gravitation, naturally the two Hydrogen atoms &, or elements [sup]2[/sup][sub]1[/sub]H & [sup]3[/sup][sub]1[/sub]H continuously traveling at the velocity of "c" contained within the E = mc[sup]2[/sup] (i.e., 1.86 10[sup]5[/sup] Mps, or 186,282.397 Mps) during the process of nuclear fusion & nuclear fission within the core of Stars Neutrons are absorbed & emitted via the binding & separating of the four fundamental forces (i.e., Strong, Electromagnetic, Weak & Gravitation).
The below image visually illustrate(s) only one of the high energy chemical reactions (i.e., Nuclear Fusion) occurring within Stars & our yellow dwarf Star..... the following end result of attempting to fuse two positively (i.e., ++) charged Hydrogen atoms together & create the nucleon element [sup]5[/sup][sub]2[/sub]He (i.e.,[sup]5[/sup][sub]2[/sub]Helium = 2 Protons ↔ 3 Neutrons) during fusion as visually illustrated below will produce the element [sup]5[/sup][sub]2[/sub]He with the nucleus of 2 Protons ↔ 3 Neutrons, in which pertaining to E = m (i.e., energy Δ matter) is electromagnetically unstable, therefore during the nuclear fusion process a free Neutron is immediately ejects with a energy of 14.1 MeV (i.e., Mega electron Volts) & the recoil energy of the remaining nucleon [sup]4[/sup][sub]2[/sub]He (i.e., 2 Protons ↔ 2 Neutrons = [sup]4[/sup][sub]2[/sub]Helium) nucleus is 3.5 MeV.
Note: Since the core of any active Star(s) posses extreme density, heat & is under extreme pressure via electromagnetic gravitation, naturally the two Hydrogen atoms &, or elements [sup]2[/sup][sub]1[/sub]H & [sup]3[/sup][sub]1[/sub]H continuously traveling at the velocity of "c" contained within the E = mc[sup]2[/sup] (i.e., 1.86 10[sup]5[/sup] Mps, or 186,282.397 Mps) during the process of nuclear fusion & nuclear fission within the core of Stars Neutrons are absorbed & emitted via the binding & separating of the four fundamental forces (i.e., Strong, Electromagnetic, Weak & Gravitation).
The below image visually illustrate(s) only one of the high energy chemical reactions (i.e., Nuclear Fusion) occurring within Stars & our yellow dwarf Star..... the following end result of attempting to fuse two positively (i.e., ++) charged Hydrogen atoms together & create the nucleon element [sup]5[/sup][sub]2[/sub]He (i.e.,[sup]5[/sup][sub]2[/sub]Helium = 2 Protons ↔ 3 Neutrons) during fusion as visually illustrated below will produce the element [sup]5[/sup][sub]2[/sub]He with the nucleus of 2 Protons ↔ 3 Neutrons, in which pertaining to E = m (i.e., energy Δ matter) is electromagnetically unstable, therefore during the nuclear fusion process a free Neutron is immediately ejects with a energy of 14.1 MeV (i.e., Mega electron Volts) & the recoil energy of the remaining nucleon [sup]4[/sup][sub]2[/sub]He (i.e., 2 Protons ↔ 2 Neutrons = [sup]4[/sup][sub]2[/sub]Helium) nucleus is 3.5 MeV.
Deuterium = [sup]2[/sup][sub]1[/sub]H (i.e.,1 Proton ↔ 1 Neutron) + Tritium = [sup]3[/sup][sub]1[/sub]H (i.e.,1 Proton ↔ 2 Neutrons) = [sup]5[/sup][sub]2[/sub]He = [sup]4[/sup][sub]2[/sub]Helium
![[serious]](/data/avatars/m/160/160873.jpg?1431539545){kind=avatar}
