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50 blessings to the first person who can correctly solve this math problem.
1
/\
\ x^(-2)
\/
-1
1
/\
\ x^(-2)
\/
-1
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Mathematical Blessings
- Thread starter WhirlwindMonk
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ralrachaan
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No right answers so far. And you aren't solving for x. The problem is sort of like 5*5. You aren't really solving for anything. You are just evaluating what is given.
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Are you looking for a simplification? And is that first part supposed to be a fraction?
Here's my attempt.
-(1/(x^2))
Here's my attempt.
-(1/(x^2))
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In words, the equation is "The integral of one over x squared in terms of x from negative one to one" Maybe that helps.
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Okay, that makes more sense.
My calc skills are rusty, but I'm thinking the answer is zero + C, where C is any real constant.
My calc skills are rusty, but I'm thinking the answer is zero + C, where C is any real constant.
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Nope. Definate integrals don't have a +C. I see what you did, and you mixed up your negatives a bit, but even if you hadn't, it still would be wrong.
This a toughy. It's lasted a little bit, so I think I'll up the ante. 150 blessings to whoever solves it.
This a toughy. It's lasted a little bit, so I think I'll up the ante. 150 blessings to whoever solves it.
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You are mixing up your integrals and derivatives.
All right, one more hint. This problem is not about being able to do the calculus. If you do the integral normally, your answer is wrong. There is something special about this problem. 25 blessings for what is special, 100 for the answer, or 150 if you can tell me both.
All right, one more hint. This problem is not about being able to do the calculus. If you do the integral normally, your answer is wrong. There is something special about this problem. 25 blessings for what is special, 100 for the answer, or 150 if you can tell me both.
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Wait a minute--I think I see. You're not taking an antidirivitive with resepect to x. So the eval would be the intigral of 1(1)^(-2) minus the integral of 1(-1)^2 which would be... what? two times the integral of x(-2)?
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*Starlight*
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There is no answer, because the function 1/(x^2) is infinite at the point x=0. Am I right? 
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starlight_86 said:There is no answer, because the function 1/(x^2) is infinite at the point x=0. Am I right?
bingo. It is an improper integral because the function becomes undefined between the limits of integration, so the answer is either undefined or infinity. That's 150 blessings! Congratulations!
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