Trinity was a 10K yield precisely because one element (uranium 235) was split into two elements (forgot which ones); their combined mass being less than that of the U235.
The missing mass is what turned into the energy that created that 10K yield. Thus, by looking at Trin's 10K yield and all its energy release, you are effectively looking at an infinite yield of that 0.1% uranium mass that was converted directly into energy. The remaining 99% remaining, finite mass ended up being those two new elements.
Again, having problems with the bolded phrasing: I don't understand what you mean by "an infinite yield of that .1% uranium mass." A
maximal yield, perhaps, in that you're converting that fraction into pure energy output (splitting the atom is ridiculously energetic after all, at least in terms of the scales involved, due to mass-energy equivalence).
But not infinite. 200 MeV/fission is hardly infinite. Surely if this were true and we obtained infinite pure energy output, Trinity would have effectively wiped out the entire universe.
Cabal, the important thing to understand is that the U235 was split, and the mass of the two remaining elements ends up being less (<--- keyword) than the original U235 element. The missing mass was converted into energy. In order for the mass to turn into energy, though, the mass had to reach a state of "infinity" first, as expressed in the Lorentz transformations.
The Lorentz transforms are used to illustrate the alteration of mass and spacetime from the p.o.v of (or observation of) a particle whose velocities are close to c. However, the only way you're going to get "infinity" mass/energy out from them would be for the neutrons/U235 nuclei to be travelling at exactly c. However, this by definition requires that infinity energy be supplied / infinite work be done on the reactant particles, which is physically impossible. This is why c is the upper speed limit, if you like, of matter with non-zero rest mass.
The Lorentz transforms don't really apply in nuclear fission as you need slow neutrons so the U235 can capture them, hence cadmium/D20 moderator in nuclear reactors. (Ok, to be fair, you don't have moderators in nuclear weaponry as statistically you'll have a few slow ones but it's thus a hugely inefficient process). The only thing that does apply is mass energy equivalence, and that at most (per fission reaction) takes the rest mass of the U235+n combo (which will always be finite) and then releases the .1% as energy via E=mc^2, which is only ever finite also, about 200 MeV/reaction.
Not trying to be a pain here, I just really don't see how "infinity" applies to this scenario as the only time it ever applies are for scenarios that are physically impossible.
On reflection, there would be very few times in physics where actual infinities are involved? As an example, one can have a half decent gravitational model describing the orbit of a small body around a large body. You can keep the larger body fixed (infinite mass) and your model works fairly well, but if you want to be ultra-precise you've got to accept that it's not infinity and instead restore the finite mass of the larger body and work a barycentre into your model. Terrible example, I know - I was just pondering this discussion earlier, and I really am finding it quite hard to think of an actual physical infinity. Sure, you can approximate to infinity a lot of the time, but that's not quite the same thing.