Elendur
Gamer and mathematician
Good. Then please keep that in mind, because I'm rather annoyed that I've had to repeat it so many times.Woah. I'm not calling you any names and I'm not trying to put words in your mouth. I'm rather enjoying a non hostile conversation between us, and I'd prefer to keep it that way.
Every photon? So you're saying that no photon can traverse any medium without interaction? (I'm not saying anything about EM fields)The fact of the matter however is that every single photon will interact with various EM field changes, various temperature gradients, and interact with the medium as it traverses spacetime. It's not like photons can weave and dodge their way around the plasmas of spacetime.
M'kay.Last week was a ridiculously busy week at work, but hopefully things will settle down a bit and I'll have time to put into studying the scattering angle issues in earnest.
You're correct, it doesn't indicate anything towards the total amount of scattering angles. It does, however, indicate something that is more important. The chance of the photons lining up.That video I cited does demonstrate the "effect" I'm trying to describe. Your small maximum possible deflection angle isn't the least bit indicative of to total amount of scattering angles that a photon might experience over time. It might *average out* to a small deflection angle, yet experience much *more* deflection than it's *averaged* defection.
Remember:
That specific angle is the maximum amount of degrees of deviation in order for the photon to reach the earth at half the distance to our nearest star.
That is what the 3.094*10^-10 degrees represents.
Now replace things, so that they have to reach something as small as a retina while still looking sharp, or near so, and whatever galaxy or star you want.
The allowed degree will be so much smaller that it's ridiculous to even try to calculate it.
Any amount? I doubt that.Well, that is exactly what would be required for "dark energy" to be responsible for *any* redshift at all. Any amount of inelastic scattering is going to first eliminate the need for dark energy. If there is *enough* scattering involved we can also do away with inflation. Either way, dark energy theory *assumes* that no other process is responsible for that redshift.
Anyways, haven't I told you that I don't care?
The video makes my point for me. Notice the angles? Where would you conclude the photons came from as the observer (the sensor)?The point of that video and link I provided is to demonstrate that deviation is acceptable. It's not as though it cannot deviate and still reach us on Earth.
Scattering Primer
Here's the video:
http://zebu.uoregon.edu/1996/ph162/images/1b3.mpg
Here's an explanation in English:
http://zebu.uoregon.edu/1996/ph162/images/v3.au
It's an issue of quantify, correct.No, it's simply physics. With enough photons, some "luck few" follow a path that leads to Earth, even if many paths do not! It's an issue of *quantify*, not a miracle.
Do you know the amount?
Do you have an estimate of the amount?
Why should I expect a significant amount of the photons to make it back into that very, extremely, narrow allowed angle?
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