If spacetime wasn't scattering the light,
That requires a couple of


!
Space-time does not scatter light except in a speculative idea for an explanation of the delay of light from blazers.
What we are talking about is:
Michael's seven noncosmological redshifts that show up in the lab
where you assert stuff about scattering in the lab without supporting it:
Michael, can you provide evidence peer-reviewed scientific literature that the following can cause cosmological redshift?
First asked14th November 2012
If you wouldn't need such long exposures
Yes scattering of light reduces intensity and makes longer exposure times needed to get images with the same brightness

.
and the images would be sharp, down to the singular star in every wavelength, in every direction, every time!
The real universe does not work like that: Scattering blurs distant galaxies compared to near galaxies.
Modern telescopes are usually
reflecting telescopes that use a parabolic mirror to focus light on a flat mirror and out to a side piece where the image is taken. Some have flat mirrors that reflect the light through the parabolic mirror.
A point source emits light in all directions. A
reflecting telescope will bounce all of the photons that hit the mirror (collected photons) to a single point (it's focal point), off the flat mirror and into the detector as a single point. A point source always produces a point image. A galaxy will always produce a sharp image of a galaxy.
N.B. This is an ideal telescope, e.g. ignoring atmosphereic effects, imperfections in the mirroes and detector, etc.
Now add some scattering. Some of the collected light will now follow paths that to the parabolic mirror look as if they came from a lot of different point sources randomly arranged around the original point source. You end up with an image that is a point source surrounded by a random set of dimmer point sources.
Scattering is a statistical process. If you have a volume in which photons are scattered before they are collected by a telescope then a certain percentage will be not scattered, a certain % scattered once, a certain % scattered twice, etc. This is represented by a mean free path for a photon.
Outer space
The sparse density of matter in outer space means that
electromagnetic radiation can travel great distances without being scattered: the
mean free path of a
photon in intergalactic space is about 1023 km, or 10 billion
light years.
[28] In spite of this,
extinction, which is the
absorption and
scattering of photons by dust and gas, is an important factor in galactic and intergalactic
astronomy.
[29]
Now point the telescope at a nearby galaxy. A number of photons will be scattered. The image will be the sharp image to be used as a reference for other images.
Point the telescope at a distant galaxy, e.g. 10 billion lightyears away. More photons will be scattered than in the first image (e.g. roughly 1/e or 37% more). The image will be blurred compared to the reference image.
The newest candidate
for the most distant object seen is MACS0647-JD
Give me a break,
Michael - you cannot understand that this is a few pixels that have been hit by photons and so the image is
pixelated 
?