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Michael, your previous conversation with me and current conversation with Loudmouth about Compton scattering suggests that you still think that there will be no blurring of distant galaxies relative to near galaxies.
We are back to discussing the Compton scattering .
Ok. I'm going to ask you something about some math.{Read but snipped due to lack of interest in most parts}
That is math for only *one* type of scattering.
How about all the rest of the various scattering methods?
Scattering - Wikipedia, the free encyclopedia
Er, no, that would be "dark energy did it".
No, my claim is that the universe is much brighter than astronomers calculated because they left out the scattering effects!
2008 | University of St Andrews
Guess why they underestimated the influence of the plasma on the photons?
That's not true. It's got lots of free electrons just like Chen's plasma.
Since it's much hotter in space than in his lab, it probably has more free electrons than Chen's plasma contains pound for pound.
All it takes is a few photon interactions per kilometer to cause a huge change in redshift over light years of distance.
Ok. I'm going to ask you something about some math.
Closest star, except our sun:
Alpha Centauri
Distance
4.2421(16) light years
4.0118*10^13 to 4.0149*10^13 km
Radius of our earth (mean value):
6,371.0 km
The maximum angle accepted before photons won't reach earth at all (the photons starting point on the star won't matter as an assumption):
Scattered at the object: invtan(6,371/(4.0118*10^13))
That results in about 1.5881*10^-10 degrees of scattering allowed.
Scattered at half the distance: invtan(6,371/(2.059*10^13))
That results in about 3.094*10^-10 degrees of scattering allowed.
Note: This is working on the assumption of one event of scattering over the entire distance, occurring at one of those two points.
Those angles would result in a nice, cosy, blanket of light from that star (since it would be scattered all over earth we wouldn't be able to discern its shape). Given that it's our closest one, it's easy to tell that all other stars would produce the same blanket effect.
Could you tell me what the maximum redshift of those scatterings would be?
Could you tell me what the maximum scattering would be (at those two points) in order for us to observe Abell 1835?
Could you tell me what the maximum redshift of those scatterings would be?
(I know there are several flaws with this, but it's a start)
Edit: I used the larger distance to calculate the maximum scattering allowed where I should have used the smaller (fixed now).
Does Compton scattering occur in the lab?
They all scatter light and suffer from the same problems.
You are handwaving away the effects that scattering has on both intensity and image quality. You have done it again here.
They are saying that dust in galaxies is obscuring the light that is reaching us. This is not intergalactic dust. This is dust in the galaxy. If it is plasma, as you want to cliam, then we should see a correlation between the size of the galaxy and redshift since larger galaxies would have more plasma.
That is not what we see. We see a correlation between distance and redshift regardless of the size of the galaxy or star cluster.
Chen's experiment also includes partially shielded hydrogen nuclei, doesn't it?
Also, the temperature and density of Chen's plasma is very different from plasma found in space, is it not?
How so?
It will also cause the light to be directed away from Earth, according to you. Therefore, we should not see any light that has been plasma redshifted.
That's more than a little "handwavy" for my tastes. Even Zwicky's motives for his mathless handwave in 1929 are questionable since he was 'selling' his own redshift theory in that particular paper.![]()
You're handwaving in those claims as well, based upon an oversimplification fallacy, so what exactly did you expect?
Er, no. Photon redshift is not related to the number of photons emitted at the source, it's related to the number of *interactions* between here and there. There is no such correlation between the size of a galaxy and the amount of redshift in tired light theory.
That's all any tired light theory would expect to see as well. You're misrepresenting the redshift process in tired light theory.
You tell me. Do you read the paper or just the abstract?
Sure, but then so is the distance involved. Somehow he has to be able to create conditions that are favorable to *measuring* the redshift in a small space. All theories must be scaled to size.
Chen wasn't working with multi-million degree plasma. The hotter plasma will result in more free electrons.
That's not what I said. I said it depends on the exact inelastic scattering mechanism, and some "luck" actually.
Does Compton Scattering occur in the lab?
Without mathematical support of your invisible friends, what *evidence* do you even have? Math and physics kinda go hand in hand.What math do you need?
So what? The very *best* images that we have of the most redshifted/distant objects in space are "pixelated" and blurred and nothing more than smudges in our highest resolution images.Non-parallel paths for photons produces blurring. Period.
And we observe some blurring in distant objects.This has been known for quite some time now. Plasma redshifts will produce non-parallel paths for photons. It will produce blurriness.
Apparently you don't understand the difference between tired light theory and PC theory, but technically there is one. I tend to promote Pantheism which is but one *subset* of PC theory that happens to include tired light theory. Even if you somehow could refute tired light theory, it would not be a falsification of PC theory, anymore than a falsification of Pantheism would be a falsification of all possible PC theories.I am not the one handwaving. That would be you. You are trying to handwave the most obvious refutation of PC.
Here is what you said:
"Not every deflection would result in blurring either. That is also a false assertion. Most *large* or *distant* deflections will simply result in a loss of light which is why the universe is twice as bright as the mainstream predicted."--MichaelYou are effectively assuming that all the plasma is concentrated in the galaxies rather than between them?Therefore, the more galactic dust a star has to shine through the more scattering one will see. The larger the galaxy, the more dust there is for the stars on the far side of the galaxy to shine through. Therefore, there should be a correlation between insensity/redshift and the size of the galaxy. That is not what we see. We see a correlation between distance and redshift.
Because scattering happens *within* them, as well as outside of them.Then why are you citing an article on scattering within galaxies.
Distance does increase the number of collisions per photon over time, just like density increases. Give it up.Distance doesn't increase density nor does it change temperature, so it is not comparable.
It depends on the *exact* interactions between particle/field and photon.The less dense the plasma the more inelastic interactions you have such as those seen in Compton scattering. Also, as RC has pointed out you can have blue shift in hot plasmas.
Brillouin scattering - Wikipedia, the free encyclopedia
Brillouin scattering is form of inelastic scattering that you keep ignoring. Any particular reason you keep ignoring the fact that Compton scattering isn't the only game in town?
No. I said if the *scattering angle is too large* we'll never see it. I also noted that some interactions allow for *no* deflection, yet loss of energy. You keep ignoring that and citing only *one* kind of scattering.You distinctly stated that if it is deflected that the photons will never reach us. That is what you have said many, many times. Therefore, we should never see this redshifted light according to you.
"Net total"? Then I'll assume you're referring to several scatterings occurring.If your intent was to impress me about how little deflection it takes to lose photons between the source and the Earth, I was already duly impressed. Keep in mind that this is a "net total" deflection. Some photons could be deflected back and forth a few times, and deflect further than your maximum in some instances, and still hit Earth.
Your question however depends on more factors that I can actually account for, other than to simply plug in the redshift numbers into Holushko's work, which frankly you're probably more adept at anyway.It took me a minute to even figure out why you used the radius of Earth rather than the diameter, not that it would have made much of a difference either way.
![]()
I've addressed scattering above, I hope you'll take a look at it.There are essentially two types of redshift effects seen in the lab. One is more of an interaction with particles in the vacuum, but there are also "magnetic field" influences that also come into play.
Brillouin scattering - Wikipedia, the free encyclopedia
I'm not sure we can say that no scattering occurs but I'm equally certain, now that I've taken the time to think about it, that scattering cannot be responsible for the redshift (if it's responsible for any redshift it would be a lot smaller than the total).Due the severe limits of particle deflection that can occur between the source and the Earth, I would tend to personally favor EM field influences and things like Brillouin scattering over something like Compton scattering. I wouldn't however rule out any form of inelastic scattering as having *some* influence on the total redshift however.
If so, as written above, the original light-emitting sources would be several magnitudes stronger than imagined (talking about hundreds of thousands times if not more).In terms of which photons reach Earth, it's just the "lucky few" that get here. The rest I would expect to scatter in the medium and be absorbed and re-emitted by various particles.
TBH, I don't see why/how I should/can discriminate between wavelengths. I can see why the medium would matter (as it's not a true vacuum) but eventually you can use a mean-value to replace it.I think if you look at the universe in a gamma-ray wavelength, you'll see that the closer galaxies *do* have a 'bright halo' compared to the background radiation coming from all directions. There are some wavelengths that work pretty much as you describe, but I suspect it depends on the wavelength and the plasma medium between here and there.
I'm not proficient enough in programming to be able to understand the code. I've looked at it but it's too complicated (I can't even find the actual calculations), to put it short.The short answer is that Holushko's C# code could "best" answer your question.
"Net total"? Then I'll assume you're referring to several scatterings occurring.
DISCLAIMER: I have not studied physics, only math for 2 years. This is entirely constructed from logical steps done by me and not read/told from anyone or any external source. I may have done mistakes by missing things and/or arrived at false conclusions.
In order to observe something, with a sharp image, we need parallel, or near so, photons from the same source.
Is that correct?
An additional demand could be that we need those photons to be from roughly the same time.
Is that correct?
Alright, then I assumed correctly (and used it as a part of my reasoning).Yes. The basic concept is that there are more interactions over distance, hence more redshift over distance. It's not *one* interaction that is responsible for the whole redshift effect, but rather it requires many such interactions. Only the 'lucky few" photons end up with a small enough "net" scattering to reach Earth.
Ok, that will not change my reasoning. Though it does change the target group, from all stars to a subset of those that has somewhat sharp images. The resulting group is still large enough for my arguments to remain valid. (IMO)More or less, but it depends on the distance. We don't actually "observe" small suns in distant galaxies as clear point sources. We observe only the largest stars, and they are typically diffuse light sources rather than clear point sources even then. What we really 'see' are a few of the emitted photons in an overall pattern that is "basically" (not necessarily perfectly) consistent with the overall layout of stars in a galaxy. Our very best technologies cannot pick out every small star in the highest redshifted galaxies as clear point sources. We don't see any distant galaxy with that kind of clarity, and our technologies are simply not that good in the first place.
Broadening of the signal will not make the photons fall outside of the time period (significantly at least). When I wrote "roughly" I meant that the photons shouldn't disperse so that the astronomical events we observe gets jumbled, time wise.The signal will broaden over time. In terms of a stable light source like a star, the overall photons spread and get intermixed with photons that left before and after that photon, but the total number of arriving photons is still quite stable.
I don't know if (/think that) this would affect my reasoning as most of it is restricted to scattering and not signal broadening.In time limited events on the other hand, such as supernova white light and gamma ray emissions from a supernova explosions, we should expect to see some time delays between various wavelengths, particularly the highest energy wavelengths. That would be a valid "test" of the theory in fact.
Alright, no rush.In terms of responding to the rest of your points, I think I need to stop here and see how you respond to the points I raised.
It seems that Brillouin (according to the wiki) doesn't apply to all photons ("fraction of the traveling light wave").I still think Brollioun scattering (or a field to field kinetic energy transfer as described by Brynjolfsson) is more likely to be the "primary" cause of redshift rather than solid particle scattering effects. That "net scattering" angles are likely to be much smaller, and the forward momentum of the photons becomes more important in such events.
I'm not sure how (/if) that would affect my reasoning. I'll therefore (no matter how just/unjust) not address this point now, I'll rethink it if you can present an argument depending on this.There can be some "blurring" going on, particularly near the point sources themselves that we would really never know anything about. All we really see are diffuse light sources anyway, particularly all small star point sources.
Neither do I, but it's a start.In short, I don't think it's quite a "simple" as you imply.
Well let see: tired light theories are wrong for one reason because astronomers like Ned Wright and Zwicky state that they cause blurring distant galaxies (relative to near galaxies).When did I *ever* make that claim RC, or did you just make that up?
Guess what - the answer is that this paper has notthing to do influence of the plasma on the photons2008 | University of St Andrews
Guess why they underestimated the influence of the plasma on the photons?
This paper shows that the existing measured output of light from galaxies consists of 11% to 87% of light emitted from interstellar dust particles (heated up by stars) and the rest directly from stars.The dominant source of electromagnetic energy in the universe today (over ultraviolet, optical, and near-infrared wavelengths) is starlight. However, quantifying the amount of starlight produced has proved difficult due to interstellar dust grains that attenuate some unknown fraction of the light. Combining a recently calibrated galactic dust model with observations of 10,000 nearby galaxies, we find that (integrated over all galaxy types and orientations) only 11% +/- 2% of the 0.1 μm photons escape their host galaxies; this value rises linearly (with logλto 87% +/- 3% at 2.1 μm. We deduce that the energy output from stars in the nearby universe is (1.6+/-0.2)×1035 W Mpc-3, of which (0.9+/-0.1)×1035 W Mpc-3 escapes directly into the intergalactic medium. Some further ramifications of dust attenuation are discussed, and equations that correct individual galaxy flux measurements for its effect are provided.
No, *you* are right back to *oversimplying* the argument by denying the physics: tired light.No, *you* are right back to *oversimplying* the argument to one and only one form of scattering when in fact there are *many* various forms that may *all* play some role in the total photon redshift from space.
There is no known interaction that can degrade a photon's energy without also changing its momentum, which leads to a blurring of distant objects which is not observed.
The tired light model does not predict the observed time dilation of high redshift supernova light curves.
The tired light model can not produce a blackbody spectrum for the Cosmic Microwave Background without some incredible coincidences.
Your whole "game" begins and ends with denial of the physics.The tired light model fails the Tolman surface brightness test.
Almost right, LoudmouthThey are saying that dust in galaxies is obscuring the light that is reaching us. This is not intergalactic dust. This is dust in the galaxy.
This has something to do with this thread how?If your intent was to impress me about how little deflection it takes to lose photons between the source and the Earth, I was already duly impressed.
he very *best* images that we have of the most redshifted/distant objects in space are "pixelated" and blurred and nothing more than smudges in our highest resolution images.
I for one ignore it because I know what Brillouin scattering is!
(my emphasis added)Brillouin scattering, named after Léon Brillouin, occurs when light in a medium (such as air, water or a crystal) interacts with time-dependent optical density variations and changes its energy (frequency) and path. The density variations may be due to acoustic modes, such as phonons, magnetic modes, such as magnons, or temperature gradients.
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The scattering is inelastic: the photon may lose energy to create a quasiparticle (Stokes process) or gain energy by destroying one (anti-Stokes process).
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Relationship to Rayleigh scattering
Rayleigh scattering, too, can be considered to be due to fluctuation in the density, composition and orientation of molecules, and hence of refraction index, in small volumes of matter (particularly in gases or liquids). The difference is that Rayleigh scattering considers only random and incoherent thermal fluctuations, in contrast with the correlated, periodic fluctuations (phonons) of Brillouin scattering.