Today at 08:06 PM Micaiah said this in Post #10
How do you use this to calculate the increases chances of survival. I am more looking for a percent increase in the chance of something surviving as a result of a beneficial mutation.
Notto has one answer. For the individual, the increase in the chance of survival is 100%. For the population, the fitness can be calculated.
Remember Hardy-Weinberg. The frequency of an allele remains unchanged from generation to generation in the absence of outside influence. Therefore, the fitness of a new mutation is defined as the ratio of the number of progeny actually produced divided by the number of progeny expected by Mendelian genetics. This is going to be greater than one in the case of favorable mutations. From that we get a selection coefficient such that fitness = 1 - s.
Now, doing the math we find that the advantageous allele A increases in frequency, per generation, by the amount delta p = (1/2)spq/(1-q).
If you look at the equation, you see that delta p is positive as long as s > 0, even if it is very small. Eventually p will equal 1, which means that
every member of the population will have the allele. Thus, a characteristic
with even a miniscule advantage will be fixed by natural selection. "Fixed" means every individual will have the allele.
So, as long as a trait is at all, even by the smallest degree, beneficial, then the odds that it will spread to become all the population is 100%.