The question is what would be the radius of a spherical shell that is 1 cm thick that had enough water to cover the world with 8 km of water.
The answer ain't 3.
The answer ain't 3.
Upvote
0
Starting today August 7th, 2024, in order to post in the Married Couples, Courting Couples, or Singles forums, you will not be allowed to post if you have your Marital status designated as private. Announcements will be made in the respective forums as well but please note that if yours is currently listed as Private, you will need to submit a ticket in the Support Area to have yours changed.
The Earth's total land surface area = 1.5 x 10[sup]8[/sup] sq km (i.e., 57,500,000 sq miles).The question is what would be the radius of a spherical shell that is 1 cm thick that had enough water to cover the world with 8 km of water.
The answer ain't 3.
Hi The Barbarian,Anyone want to calculate the energy of that much water falling back to Earth and the consequences thereof?
Anyone want to calculate the energy of that much water falling back to Earth and the consequences thereof?
Hi TemperateSeaIsland,Calculating the velocity would be tricky. I'll then just give it a velocity of 100 m/s, no idea how accurate that will be I suspect much much slower than in reality.
The water will have a mass of 4.1 x 10[sup]21[/sup] Kg
So the kinetic energy will be E = 1/2 . 4.1 x 10[sup]21[/sup] . 100[sup]2[/sup]
Giving 2.05 x 10[sup]25[/sup] Joules of energy, which if wiki is to believed about 4 times the energy we recieve from the Sun over a year.
I think it would be bad.
Hi TemperateSeaIsland,
Here's something that you may find interesting..... (pertaining to E = m) According to your Wiki-link:
The total energy (i.e., E = m) output of the Sun, our yellow-dwarf Star (even though the E = m is 1 x 10[sup]6[/sup] years old) each day the Sun produces 3.34 x 10[sup]31[/sup]J x 365 = 1.2191 x 10[sup]34[/sup]J
5.5×10[sup]24[/sup] J, the total energy from the Sun that strikes the face of the Earth each year
Some many various complexities of (E = m, or) energy:Calculating the velocity would be tricky. I'll then just give it a velocity of 100 m/s, no idea how accurate that will be I suspect much much slower than in reality.
The water will have a mass of 4.1 x 10[sup]21[/sup] Kg
So the kinetic energy will be E = 1/2 . 4.1 x 10[sup]21[/sup] . 100[sup]2[/sup]
Giving 2.05 x 10[sup]25[/sup] Joules of energy, which if wiki is to believed about 4 times the energy we recieve from the Sun over a year.
I think it would be bad.
Hi The Barbarian,
I would like to calculate it for everyone.
Water = H[sub]2[/sub]O, (i.e., HOH)
1 Oxygen molecule = 1,313.9kJ·mol[sup]−1[/sup]
1313 kJ/mol-1 looks familiar, but... Ionization potential is a measurement of the amount of energy it takes to remove one mole of electrons from one mole of a gaseous element.
Your calculation quantifies the amount of energy one would need to remove 3 moles of electrons per mole of water, after the water has been separated into its atomic, gaseous constituents.
Which is to say; Whiskey..? Tango..? Foxtrot..? Your calculation has nothing to do with the question asked.
What, after all, do you expect from Captain Cut n' Paste? You didnt imagine he understand s any of the stuff he posts, do you?
Don't calculate the velocity -- just calculate the difference in potential energy for that mass at the different radii (U = -GMm/r). The result is 2.5 x10[sup]29[/sup] J. That's a lot of energy.Calculating the velocity would be tricky. I'll then just give it a velocity of 100 m/s, no idea how accurate that will be I suspect much much slower than in reality.
Don't calculate the velocity -- just calculate the difference in potential energy for that mass at the different radii (U = -GMm/r). The result is 2.5 x10[sup]29[/sup] J. That's a lot of energy.
..........![]()
![]()