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Discussion and Debate
Discussion and Debate
Physical & Life Sciences
Electrons and Inertial Frames
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<blockquote data-quote="essentialsaltes" data-source="post: 74995206" data-attributes="member: 294566"><p>I think better yet, we speak of the electron being in a particular quantum state (which is associated with a particular quantum wave-function), and yes each quantum state is associated with a particular energy. The quantum state is described by the usual <a href="https://en.wikipedia.org/wiki/Quantum_number#Common_terminology" target="_blank">4 quantum numbers</a>:</p><p></p><p>n = 'electron shell'</p><p>l = angular momentum</p><p>lz = angular momentum with respect to z-axis</p><p>s = spin (up or down)</p><p></p><p></p><p></p><p>I'm not quite sure what you mean by a 'closed surface'. If you map out the wavefunctions (yes equivalent to taking position measurements on an electron in that state over and over again) <a href="https://en.wikipedia.org/wiki/Atomic_orbital#/media/File:Hydrogen_Density_Plots.png" target="_blank">they are three-dimensional 'clouds' of probability</a>. They do not look like circular orbits.</p><p></p><p>Worse yet, many of the allowed quantum states allow the angular momentum to be zero. So most of the spherically symmetric solutions (that might look kinda like orbits) have no angular momentum, so the electron is not 'going around' the nucleus if we try to make a classical picture of the quantum state.</p></blockquote><p></p>
[QUOTE="essentialsaltes, post: 74995206, member: 294566"] I think better yet, we speak of the electron being in a particular quantum state (which is associated with a particular quantum wave-function), and yes each quantum state is associated with a particular energy. The quantum state is described by the usual [URL='https://en.wikipedia.org/wiki/Quantum_number#Common_terminology']4 quantum numbers[/URL]: n = 'electron shell' l = angular momentum lz = angular momentum with respect to z-axis s = spin (up or down) I'm not quite sure what you mean by a 'closed surface'. If you map out the wavefunctions (yes equivalent to taking position measurements on an electron in that state over and over again) [URL='https://en.wikipedia.org/wiki/Atomic_orbital#/media/File:Hydrogen_Density_Plots.png']they are three-dimensional 'clouds' of probability[/URL]. They do not look like circular orbits. Worse yet, many of the allowed quantum states allow the angular momentum to be zero. So most of the spherically symmetric solutions (that might look kinda like orbits) have no angular momentum, so the electron is not 'going around' the nucleus if we try to make a classical picture of the quantum state. [/QUOTE]
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