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Tomk80

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Is it true that n/∞ = 0?

No. It is arbitrarily close to 0, not 0. Although that statement is also incorrect.

Infinity is a concept, not a number. You cannot divide by a concept.

Dividing by infinity is shorthand for the limit of p going to inifinity for n / p. Which basically means that if you divide by successively higher numbers, the result is going to be successively closer to 0.
 
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Elendur

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Infinity needs some very cool extensions to the regular axiomatic approach.
Therefore you'll need some unique, high level math to deal with n/∞ = 0 since the real axis usually doesn't include ∞.
The interval (∞,&#8734 means that it includes all values up to, but not including, infinity.

You can let something go towards infinity, with the limit definition.

If you take lim[h->∞](n/h) then you can say it equals 0 since it'll be infinitely close to 0. The same way 0.99999... = 1.

I might have got something wrong here, I didn't reference any specific source and I'm not so well versed in the concept of infinity.
 
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AV1611VET

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Okay, thank you.
 
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RickG

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Is it true that n/∞ = 0?

Solving:

n = 0 (&#8734 ; anything multiplied 0 is 0.

but, what if you said n/∞ = 1 ; different story. n = 1(&#8734 or simply ∞.

BTW, what is "n"? It would be nice to know what you are dividing infinity into.
 
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AV1611VET

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Solving:

n = 0 (&#8734 ; anything multiplied 0 is 0.

but, what if you said n/∞ = 1 ; different story. n = 1(&#8734 or simply ∞.

BTW, what is "n"? It would be nice to know what you are dividing infinity into.
Doesn't n in an equation stand for "number" -- as in any number?
 
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RickG

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Doesn't n in an equation stand for "number" -- as in any number?

Yes, but that number stands for something. What is n, a distance, temperature, time, rate, etc..

Also, infinity cannot be zero by definition. Infinity is an unbound limit, therefore it has a value. Simply put infinity always increases or decreases without bounds.

Having said that, there is an exception when describing a one dimensional Riemann surface. That is a really interesting area of mathematics (geometry) but also gets pretty complicated.

May I ask what the point of the OP is?
 
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Lethe

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Taking your last statement to be the case, that infinity is shorthand for the limit of p going to infinity for n/p, there are at least two proofs I can think of to demonstrate the equivalency of lim_p->inf of n/p and 0.

They are equal.
 
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Lethe

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Hmm.... I'm thinking of the proof of 0.9 repeating being equal to one.

0.9 repeating to the nth decimal place is equivalent to 1-1/(10^n)

0.9 repeating is equivalent to the limit n -> inf of (1 - 1/ (10^n) ).

and there are two proofs I can think of showing that 0.9 repeating are equivalent to one.

Therefore 1 = 1 - lim (1 / (10^n) ) => lim 1/ (10^n) = 0

And since 10^n is a monotonic sequence, there's a 1:1 mapping from n to 10^n.

Isn't that about right?
 
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AV1611VET

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I happened to run across this:
For those that have not worked with infinite number sets,

2 x (infinity) = infinity
AND
(any number)/(infinity) = 0.
... and was curious.

QV the OP in that thread as well.
 
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