If a real physicist would like to take a shot at this please PM me. The answer is not that difficult. I may have to watch the way that I ask this since I have seen the correct answer figure out on the internet. I ran into this many years ago, long before the internet:
The wording might be a bit awkward to keep people from cheating. You have a sphere of radius R. It is of constant density p (sorry, I don't have a rho), with the exception of another sphere totally within the solid sphere. The small sphere is totally empty. They are not concentric. It has a radius r, and its center has the coordinate a,b,c in a standard xyz, coordinate system where the origin is at the center of the large, almost solid, sphere.
I need a formula that describes the value of g (the acceleration due to gravity) within the small hollow.
This is a fairly easy problem for a physicist. We had one pretender here who claimed he was a physicist but never even took a shot at this problem.
I do know the answer. I can show the math of the answer. If the EU people can do this I will grant that they can at least do some physics. Until then.... well the lack of an answer will speak for itself.
The wording might be a bit awkward to keep people from cheating. You have a sphere of radius R. It is of constant density p (sorry, I don't have a rho), with the exception of another sphere totally within the solid sphere. The small sphere is totally empty. They are not concentric. It has a radius r, and its center has the coordinate a,b,c in a standard xyz, coordinate system where the origin is at the center of the large, almost solid, sphere.
I need a formula that describes the value of g (the acceleration due to gravity) within the small hollow.
This is a fairly easy problem for a physicist. We had one pretender here who claimed he was a physicist but never even took a shot at this problem.
I do know the answer. I can show the math of the answer. If the EU people can do this I will grant that they can at least do some physics. Until then.... well the lack of an answer will speak for itself.