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Latest edit - Oops, my theory has a flaw, go to post number 3 in this thread....
The number of the beast's name is 666. If it follows gematria (which that might not be the case at all), then in the name, these letters must appear within the name having one of these combo's to get that last 6 of 666
For example, to get six, using an "e", somewhere in the name, there also has to be an "a".
base numerical equivalents:
1 a
2 b
3 c
4 d
5 e
6 f
______________________________________________________________
to get 6, here are the combos:
f
e a
d b, d a a
c c, c b a, c a a a
b b b, bbaa, b a a a a
a a a a a a
______________________________________________________________
We can probably throw out "a a a a a a" as unllkey, too many a's for a person's name. Also the same for "b b b", "bbaa" , and b a a a a". So that would leave....
f
e a
d b, d a a
c c, c b a, c a a a
_______________________________________________________________
I'm thinking "c a a a" is another unlikely combo. That leaves.....
f
e a
d b, d a a
c c, c b a,
So what I am saying is to focus on that last six. For example, in the name "Solomon", there is no "6" combo in that name. Whether the name of the beast is one name or a first name and last name, we don't know.
But here is another clue, the person's name also is to be imprinted on the hand or forehead, so it is probably not a long name. Maybe a short name, or a short first name and short last name.
Some-one with computer programming skills could write a program, using those combos, to go through different data bases of names and see what turns up - to, firstly, to see which names contain the last six. Creating a list of potential names.
Once that list of "6" in the name found. Then run another gematria program, of only those names - to see which of those yield the "666".
Of course, a computer program could go through a data base calculation name values without two steps involved. So maybe my idea is only good for someone, apart from a computer program, who is trying to eliminate names quickly.
The number of the beast's name is 666. If it follows gematria (which that might not be the case at all), then in the name, these letters must appear within the name having one of these combo's to get that last 6 of 666
For example, to get six, using an "e", somewhere in the name, there also has to be an "a".
base numerical equivalents:
1 a
2 b
3 c
4 d
5 e
6 f
______________________________________________________________
to get 6, here are the combos:
f
e a
d b, d a a
c c, c b a, c a a a
b b b, bbaa, b a a a a
a a a a a a
______________________________________________________________
We can probably throw out "a a a a a a" as unllkey, too many a's for a person's name. Also the same for "b b b", "bbaa" , and b a a a a". So that would leave....
f
e a
d b, d a a
c c, c b a, c a a a
_______________________________________________________________
I'm thinking "c a a a" is another unlikely combo. That leaves.....
f
e a
d b, d a a
c c, c b a,
So what I am saying is to focus on that last six. For example, in the name "Solomon", there is no "6" combo in that name. Whether the name of the beast is one name or a first name and last name, we don't know.
But here is another clue, the person's name also is to be imprinted on the hand or forehead, so it is probably not a long name. Maybe a short name, or a short first name and short last name.
Some-one with computer programming skills could write a program, using those combos, to go through different data bases of names and see what turns up - to, firstly, to see which names contain the last six. Creating a list of potential names.
Once that list of "6" in the name found. Then run another gematria program, of only those names - to see which of those yield the "666".
Of course, a computer program could go through a data base calculation name values without two steps involved. So maybe my idea is only good for someone, apart from a computer program, who is trying to eliminate names quickly.
Last edited:
