After a quick scan of the previous thread, I noticed some of these points touched upon, but not examined in depth:
Issue One: Volume of water required.
The flood covered the planet (according to Genesis) and Mount Everest is 8,848 meters tall. The diameter of the earth at the equator, is 12,756.8 km. We need to calculate the volume of water to fill a sphere with a radius of the Earth plus Everest; then subtract the volume of a sphere with a radius of the Earth. This isnt perfect, but close enough.
Everest
V= 4/3 * pi * 6387.248 km cubed
V= 1.09151 x 10 to the 12 cubic kilometres (1.09151e2 km3)
Earth at sea level
V= 4/3 * pi * 6378.4 km cubed
V = 1.08698 x 10 to the 12 cubic kilometres (1.08698e12 km3)
The difference between these two figures is the amount of water needed to just cover the Earth: 4.525 x 10 to the ninth cubic kilometers (4,525,000,000,000). Where did all that water come from?
Issue Two: The weight of all that water.
Water at STP weighs in at 1 gram/cubic centimeter:
4.252e09 km3 of water,
X 106 (= cubic meters),
X 106 (= cubic centimeters),
X 1 g/cm3 (= grams),
X 10-3 (= kilograms),
equals 4.525e21 kg.
The mass of the earth is 5.972e24 kg!
What are the effects of that much weight? In the Pleistocene, continental ice sheets covered many of the northern states and most all of Canada. Well call the area covered by the Wisconsinian advance was 10,000,000,000 km2, by an average thickness of 1 km of ice (a good estimate... lots of places online to confirm this). 1.00x1007 km2 X 1 km thickness equals 1.00E+07 km3 of ice. The weight of all that ice is just about 0.23% of the water needed for the flood.
The Wisconsinian advance ended about 25,000 years ago, and the flood about 4,000 years ago. Due to these late Pleistocene glaciations the mass of the ice has depressed the crust of the Earth. Now that the ice is gone, the crust is slowly rising (called glacial rebound); and this rebound can be measured, in places (like northern Wisconsin), in centimetres/year. Glacial rebound can only be measured, obviously, in glaciated areas (the Sahara is not rebounding as it was not glaciated during the Pleistocene). So why dont we see global rebound from the more recent flood?
Issue Three: Kinetic energy release of 40 days of global rain.
Were going to assume that enough rain fell in 40 days to result in the water volume calculated in Issue One. The amount of mass falling to Earth is 1.10675e20 kilograms daily. The energy released each day is 1.73584e25 joules. The amount of energy the Earth would have to radiate per m2/sec is energy divided by surface area of the Earth times number of seconds in one day. That is: e = 1.735384e25/(4*3.14159* ((6386)2*86,400)) = 391,935.0958 j/m2/s.
Currently, the Earth radiates energy at the rate of approximately 215 joules/m2/sec and the average temperature is 280 K. Using the Stefan- Boltzman 4'th power law to calculate the increase in temperature:
E (increase)/E (normal) = T (increase)/T4 (normal)
E (normal) = 215
E (increase) = 391,935.0958
T (normal) = 280.
and T (increase) equals 1800 K.
The temperature would rise 1800 K, or 1,526, or 2,780. Obviously, this is a temperature the earth and Noah could not survive. Even if the rain accounted for only 10% of the flood waters, the teperature is much too high.
Issue One: Volume of water required.
The flood covered the planet (according to Genesis) and Mount Everest is 8,848 meters tall. The diameter of the earth at the equator, is 12,756.8 km. We need to calculate the volume of water to fill a sphere with a radius of the Earth plus Everest; then subtract the volume of a sphere with a radius of the Earth. This isnt perfect, but close enough.
Everest
V= 4/3 * pi * 6387.248 km cubed
V= 1.09151 x 10 to the 12 cubic kilometres (1.09151e2 km3)
Earth at sea level
V= 4/3 * pi * 6378.4 km cubed
V = 1.08698 x 10 to the 12 cubic kilometres (1.08698e12 km3)
The difference between these two figures is the amount of water needed to just cover the Earth: 4.525 x 10 to the ninth cubic kilometers (4,525,000,000,000). Where did all that water come from?
Issue Two: The weight of all that water.
Water at STP weighs in at 1 gram/cubic centimeter:
4.252e09 km3 of water,
X 106 (= cubic meters),
X 106 (= cubic centimeters),
X 1 g/cm3 (= grams),
X 10-3 (= kilograms),
equals 4.525e21 kg.
The mass of the earth is 5.972e24 kg!
What are the effects of that much weight? In the Pleistocene, continental ice sheets covered many of the northern states and most all of Canada. Well call the area covered by the Wisconsinian advance was 10,000,000,000 km2, by an average thickness of 1 km of ice (a good estimate... lots of places online to confirm this). 1.00x1007 km2 X 1 km thickness equals 1.00E+07 km3 of ice. The weight of all that ice is just about 0.23% of the water needed for the flood.
The Wisconsinian advance ended about 25,000 years ago, and the flood about 4,000 years ago. Due to these late Pleistocene glaciations the mass of the ice has depressed the crust of the Earth. Now that the ice is gone, the crust is slowly rising (called glacial rebound); and this rebound can be measured, in places (like northern Wisconsin), in centimetres/year. Glacial rebound can only be measured, obviously, in glaciated areas (the Sahara is not rebounding as it was not glaciated during the Pleistocene). So why dont we see global rebound from the more recent flood?
Issue Three: Kinetic energy release of 40 days of global rain.
Were going to assume that enough rain fell in 40 days to result in the water volume calculated in Issue One. The amount of mass falling to Earth is 1.10675e20 kilograms daily. The energy released each day is 1.73584e25 joules. The amount of energy the Earth would have to radiate per m2/sec is energy divided by surface area of the Earth times number of seconds in one day. That is: e = 1.735384e25/(4*3.14159* ((6386)2*86,400)) = 391,935.0958 j/m2/s.
Currently, the Earth radiates energy at the rate of approximately 215 joules/m2/sec and the average temperature is 280 K. Using the Stefan- Boltzman 4'th power law to calculate the increase in temperature:
E (increase)/E (normal) = T (increase)/T4 (normal)
E (normal) = 215
E (increase) = 391,935.0958
T (normal) = 280.
and T (increase) equals 1800 K.
The temperature would rise 1800 K, or 1,526, or 2,780. Obviously, this is a temperature the earth and Noah could not survive. Even if the rain accounted for only 10% of the flood waters, the teperature is much too high.
